Suppose for some day, we have $n-m=k$. Then,
$n-m = k $
$2n-2m = 2k $
$2n-2-2m-2 = 2k-2-2 = 2k-4 $
$ (2n-2)-(2m+2) = 2k-4$
That means the difference will be $2k-4$ on the next day. From this, it's easy to see that when $k<4$, the difference will keep decreasing each day and eventually Payel's number will become larger. On the other hand, when $k\geq4$, the difference does not decrease. Therefore, our answer is $x=4$.