For Part B, use induction and divide the last three rows into some parts.

Definition: Call flipping the sides of three coins that are touching each other a move. Alternating a triangle of size $n$ means flipping the sides of all the coins of that triangle by performing a series of moves.

A. Perform moves on the three corner triangles of size $1$ one by one and then perform a move on the center triangle of size $1$.

B. We prove this by induction. Base case $n=3$ is already shown. Now suppose we can alternate a triangle of size $n=3k$. We will show that we can also alternate the triangle of size $n=3(k+1)$. In this triangle, first alternate the top $3k$ part. Then, the remaining bottom three rows can be divided into parts like below:

There will be a triangle of size $1$ or $3$ at the end depending on whether $n$ is even or odd. Notice that all these parts can be alternated easily and we are done.